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-40=1-(5/2)d
We move all terms to the left:
-40-(1-(5/2)d)=0
Domain of the equation: 2)d)!=0We add all the numbers together, and all the variables
d!=0/1
d!=0
d∈R
-(1-(+5/2)d)-40=0
We multiply all the terms by the denominator
-(1-(+5-40*2)d)=0
We calculate terms in parentheses: -(1-(+5-40*2)d), so:We get rid of parentheses
1-(+5-40*2)d
determiningTheFunctionDomain -(+5-40*2)d+1
We add all the numbers together, and all the variables
-(-75)d+1
We multiply parentheses
75d+1
Back to the equation:
-(75d+1)
-75d-1=0
We move all terms containing d to the left, all other terms to the right
-75d=1
d=1/-75
d=-1/75
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