-40x2+-13x+1=0

Solution for -40x2+-13x+1=0 equation:

-40x^2+-13x+1=0

We add all the numbers together, and all the variables

-40x^2-13x=0

a = -40; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·(-40)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*-40}=\frac{0}{-80}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*-40}=\frac{26}{-80}
=-13/40
$