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-40x^2+600x-2000=0
a = -40; b = 600; c = -2000;
Δ = b2-4ac
Δ = 6002-4·(-40)·(-2000)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-200}{2*-40}=\frac{-800}{-80} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+200}{2*-40}=\frac{-400}{-80} =+5 $
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