-40x2-3x+1=0

Solution for -40x2-3x+1=0 equation:

-40x^2-3x+1=0

a = -40; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·(-40)·1
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-13}{2*-40}=\frac{-10}{-80}
=1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+13}{2*-40}=\frac{16}{-80}
=-1/5
$