-41+10y+4=3(4y-4)-7

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Solution for -41+10y+4=3(4y-4)-7 equation: 



-41+10y+4=3(4y-4)-7

We move all terms to the left:

-41+10y+4-(3(4y-4)-7)=0

We add all the numbers together, and all the variables

10y-(3(4y-4)-7)-37=0



We calculate terms in parentheses: -(3(4y-4)-7), so:

3(4y-4)-7

We multiply parentheses

12y-12-7

We add all the numbers together, and all the variables

12y-19

Back to the equation:

-(12y-19)



We get rid of parentheses

10y-12y+19-37=0

We add all the numbers together, and all the variables

-2y-18=0

We move all terms containing y to the left, all other terms to the right

-2y=18

y=18/-2

y=-9

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