-42+9y+8=3(4y-5)-4

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Solution for -42+9y+8=3(4y-5)-4 equation: 



-42+9y+8=3(4y-5)-4

We move all terms to the left:

-42+9y+8-(3(4y-5)-4)=0

We add all the numbers together, and all the variables

9y-(3(4y-5)-4)-34=0



We calculate terms in parentheses: -(3(4y-5)-4), so:

3(4y-5)-4

We multiply parentheses

12y-15-4

We add all the numbers together, and all the variables

12y-19

Back to the equation:

-(12y-19)



We get rid of parentheses

9y-12y+19-34=0

We add all the numbers together, and all the variables

-3y-15=0

We move all terms containing y to the left, all other terms to the right

-3y=15

y=15/-3

y=-5

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