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-45x+15x^2=10x
We move all terms to the left:
-45x+15x^2-(10x)=0
We add all the numbers together, and all the variables
15x^2-55x=0
a = 15; b = -55; c = 0;
Δ = b2-4ac
Δ = -552-4·15·0
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-55}{2*15}=\frac{0}{30} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+55}{2*15}=\frac{110}{30} =3+2/3 $
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