-48+1x=-8(7+x)10x

Solution for -48+1x=-8(7+x)10x equation:

-48+1x=-8(7+x)10x

We move all terms to the left:

-48+1x-(-8(7+x)10x)=0

We add all the numbers together, and all the variables

1x-(-8(x+7)10x)-48=0

We add all the numbers together, and all the variables

x-(-8(x+7)10x)-48=0


We calculate terms in parentheses: -(-8(x+7)10x), so:

-8(x+7)10x

We multiply parentheses

-80x^2-560x

Back to the equation:

-(-80x^2-560x)


We get rid of parentheses

80x^2+560x+x-48=0

We add all the numbers together, and all the variables

80x^2+561x-48=0

a = 80; b = 561; c = -48;
Δ = b2-4ac
Δ = 5612-4·80·(-48)
Δ = 330081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(561)-\sqrt{330081}}{2*80}=\frac{-561-\sqrt{330081}}{160}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(561)+\sqrt{330081}}{2*80}=\frac{-561+\sqrt{330081}}{160}
$