-48+4y+9=2(4y-4)-7

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Solution for -48+4y+9=2(4y-4)-7 equation: 



-48+4y+9=2(4y-4)-7

We move all terms to the left:

-48+4y+9-(2(4y-4)-7)=0

We add all the numbers together, and all the variables

4y-(2(4y-4)-7)-39=0



We calculate terms in parentheses: -(2(4y-4)-7), so:

2(4y-4)-7

We multiply parentheses

8y-8-7

We add all the numbers together, and all the variables

8y-15

Back to the equation:

-(8y-15)



We get rid of parentheses

4y-8y+15-39=0

We add all the numbers together, and all the variables

-4y-24=0

We move all terms containing y to the left, all other terms to the right

-4y=24

y=24/-4

y=-6

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