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-48/y=8-y
We move all terms to the left:
-48/y-(8-y)=0
Domain of the equation: y!=0We add all the numbers together, and all the variables
y∈R
-48/y-(-1y+8)=0
We get rid of parentheses
-48/y+1y-8=0
We multiply all the terms by the denominator
1y*y-8*y-48=0
We add all the numbers together, and all the variables
-8y+1y*y-48=0
Wy multiply elements
y^2-8y-48=0
a = 1; b = -8; c = -48;
Δ = b2-4ac
Δ = -82-4·1·(-48)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-16}{2*1}=\frac{-8}{2} =-4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+16}{2*1}=\frac{24}{2} =12 $
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