-48=-6(1-x)+4(x+2)

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Solution for -48=-6(1-x)+4(x+2) equation: 



-48=-6(1-x)+4(x+2)

We move all terms to the left:

-48-(-6(1-x)+4(x+2))=0

We add all the numbers together, and all the variables

-(-6(-1x+1)+4(x+2))-48=0



We calculate terms in parentheses: -(-6(-1x+1)+4(x+2)), so:

-6(-1x+1)+4(x+2)

We multiply parentheses

6x+4x-6+8

We add all the numbers together, and all the variables

10x+2

Back to the equation:

-(10x+2)



We get rid of parentheses

-10x-2-48=0

We add all the numbers together, and all the variables

-10x-50=0

We move all terms containing x to the left, all other terms to the right

-10x=50

x=50/-10

x=-5

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