-48=-6(4+2z)

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Solution for -48=-6(4+2z) equation: 



-48=-6(4+2z)

We move all terms to the left:

-48-(-6(4+2z))=0

We add all the numbers together, and all the variables

-(-6(2z+4))-48=0



We calculate terms in parentheses: -(-6(2z+4)), so:

-6(2z+4)

We multiply parentheses

-12z-24

Back to the equation:

-(-12z-24)



We get rid of parentheses

12z+24-48=0

We add all the numbers together, and all the variables

12z-24=0

We move all terms containing z to the left, all other terms to the right

12z=24

z=24/12

z=2

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