-48m-3m2=8m-4m2

Solution for -48m-3m2=8m-4m2 equation:

-48m-3m^2=8m-4m^2

We move all terms to the left:

-48m-3m^2-(8m-4m^2)=0

We get rid of parentheses

-3m^2+4m^2-8m-48m=0

We add all the numbers together, and all the variables

m^2-56m=0

a = 1; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·1·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*1}=\frac{0}{2}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*1}=\frac{112}{2}
=56
$