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-49=5(2x-1)-5+3x
We move all terms to the left:
-49-(5(2x-1)-5+3x)=0
We calculate terms in parentheses: -(5(2x-1)-5+3x), so:We get rid of parentheses
5(2x-1)-5+3x
determiningTheFunctionDomain 5(2x-1)+3x-5
We add all the numbers together, and all the variables
3x+5(2x-1)-5
We multiply parentheses
3x+10x-5-5
We add all the numbers together, and all the variables
13x-10
Back to the equation:
-(13x-10)
-13x+10-49=0
We add all the numbers together, and all the variables
-13x-39=0
We move all terms containing x to the left, all other terms to the right
-13x=39
x=39/-13
x=-3
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