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-49=5(2x-1)/2-5=-30
We move all terms to the left:
-49-(5(2x-1)/2-5)=0
We multiply all the terms by the denominator
-(5(2x-1)-49*2-5)=0
We calculate terms in parentheses: -(5(2x-1)-49*2-5), so:We get rid of parentheses
5(2x-1)-49*2-5
determiningTheFunctionDomain 5(2x-1)-5-49*2
We add all the numbers together, and all the variables
5(2x-1)-103
We multiply parentheses
10x-5-103
We add all the numbers together, and all the variables
10x-108
Back to the equation:
-(10x-108)
-10x+108=0
We move all terms containing x to the left, all other terms to the right
-10x=-108
x=-108/-10
x=10+4/5
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