-4=(1/3)z+2

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Solution for -4=(1/3)z+2 equation: 



-4=(1/3)z+2

We move all terms to the left:

-4-((1/3)z+2)=0



Domain of the equation: 3)z+2)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

-((+1/3)z+2)-4=0

We multiply all the terms by the denominator


-((+1-4*3)z+2)=0



We calculate terms in parentheses: -((+1-4*3)z+2), so:

(+1-4*3)z+2

We add all the numbers together, and all the variables

(-11)z+2

We multiply parentheses

-11z+2

Back to the equation:

-(-11z+2)



We get rid of parentheses

11z-2=0

We move all terms containing z to the left, all other terms to the right

11z=2

z=2/11

z=2/11

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