-4=-2/3(n-18)

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Solution for -4=-2/3(n-18) equation:



-4=-2/3(n-18)
We move all terms to the left:
-4-(-2/3(n-18))=0
Domain of the equation: 3(n-18))!=0
n∈R
We multiply all the terms by the denominator
-(-2-4*3(n-18))=0
We calculate terms in parentheses: -(-2-4*3(n-18)), so:
-2-4*3(n-18)
determiningTheFunctionDomain -4*3(n-18)-2
Wy multiply elements
-12n(n-2
Back to the equation:
-(-12n(n-2)
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
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We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
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We calculate terms in parentheses: -(-12n(n-2), so:
-12n(n-2
We calculate terms in parentheses: -(-12n(n-2), so:
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We calculate terms in parentheses: -(-12n(n-2), so:
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