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-4=1/2(10w+12)+5w
We move all terms to the left:
-4-(1/2(10w+12)+5w)=0
Domain of the equation: 2(10w+12)+5w)!=0We multiply all the terms by the denominator
w∈R
-(1-4*2(10w+12)+5w)=0
We calculate terms in parentheses: -(1-4*2(10w+12)+5w), so:We add all the numbers together, and all the variables
1-4*2(10w+12)+5w
determiningTheFunctionDomain -4*2(10w+12)+5w+1
We add all the numbers together, and all the variables
5w-4*2(10w+12)+1
Wy multiply elements
5w-8w(1+1
Back to the equation:
-(5w-8w(1+1)
-(5w-8w2=0
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