-4=2(n-1)-(2+4n)

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Solution for -4=2(n-1)-(2+4n) equation: 



-4=2(n-1)-(2+4n)

We move all terms to the left:

-4-(2(n-1)-(2+4n))=0

We add all the numbers together, and all the variables

-(2(n-1)-(4n+2))-4=0



We calculate terms in parentheses: -(2(n-1)-(4n+2)), so:

2(n-1)-(4n+2)

We multiply parentheses

2n-(4n+2)-2

We get rid of parentheses

2n-4n-2-2

We add all the numbers together, and all the variables

-2n-4

Back to the equation:

-(-2n-4)



We get rid of parentheses

2n+4-4=0

We add all the numbers together, and all the variables

2n=0

n=0/2

n=0

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