-4=2(x+4)2x

Solution for -4=2(x+4)2x equation:

-4=2(x+4)2x

We move all terms to the left:

-4-(2(x+4)2x)=0


We calculate terms in parentheses: -(2(x+4)2x), so:

2(x+4)2x

We multiply parentheses

4x^2+16x

Back to the equation:

-(4x^2+16x)


We get rid of parentheses

-4x^2-16x-4=0

a = -4; b = -16; c = -4;
Δ = b2-4ac
Δ = -162-4·(-4)·(-4)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{3}}{2*-4}=\frac{16-8\sqrt{3}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{3}}{2*-4}=\frac{16+8\sqrt{3}}{-8}
$