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-4=2/3(-4)+b
We move all terms to the left:
-4-(2/3(-4)+b)=0
Domain of the equation: 3(-4)+b)!=0We multiply all the terms by the denominator
b∈R
-(2-4*3(-4)+b)=0
We calculate terms in parentheses: -(2-4*3(-4)+b), so:We get rid of parentheses
2-4*3(-4)+b
determiningTheFunctionDomain b+2-4*3(-4)
We add all the numbers together, and all the variables
b+50
Back to the equation:
-(b+50)
-b-50=0
We add all the numbers together, and all the variables
-1b-50=0
We move all terms containing b to the left, all other terms to the right
-b=50
b=50/-1
b=-50
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