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-4=5-3(5p+3)
We move all terms to the left:
-4-(5-3(5p+3))=0
We calculate terms in parentheses: -(5-3(5p+3)), so:We get rid of parentheses
5-3(5p+3)
determiningTheFunctionDomain -3(5p+3)+5
We multiply parentheses
-15p-9+5
We add all the numbers together, and all the variables
-15p-4
Back to the equation:
-(-15p-4)
15p+4-4=0
We add all the numbers together, and all the variables
15p=0
p=0/15
p=0
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