-4a+15=3-5(a-2)

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Solution for -4a+15=3-5(a-2) equation: 



-4a+15=3-5(a-2)

We move all terms to the left:

-4a+15-(3-5(a-2))=0



We calculate terms in parentheses: -(3-5(a-2)), so:

3-5(a-2)

determiningTheFunctionDomain
-5(a-2)+3

We multiply parentheses

-5a+10+3

We add all the numbers together, and all the variables

-5a+13

Back to the equation:

-(-5a+13)



We get rid of parentheses

-4a+5a-13+15=0

We add all the numbers together, and all the variables

a+2=0

We move all terms containing a to the left, all other terms to the right

a=-2

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