-4a-1/-10a=3/a

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Solution for -4a-1/-10a=3/a equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

-4*a-((1/(-10))*a) = 3/a // - 3/a

-4*a-((1/(-10))*a)-(3/a) = 0

(1/10)*a-4*a-3*a^-1 = 0

-39/10*a^1-3*a^-1 = 0

(-39/10*a^2-3*a^0)/(a^1) = 0 // * a^2

a^1*(-39/10*a^2-3*a^0) = 0

a^1

(-39/10)*a^2-3 = 0

(-39/10)*a^2-3 = 0

DELTA = 0^2-(-3*4*(-39/10))

DELTA = -234/5

DELTA < 0

a in { } 

a belongs to the empty set

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