-4a=-6-(1+5a

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Solution for -4a=-6-(1+5a equation: 



-4a=-6-(1+5a

We move all terms to the left:

-4a-(-6-(1+5a)=0

We add all the numbers together, and all the variables

-4a-(-6-(5a+1)=0



We calculate terms in parentheses: -(-6-(5a+1), so:

-6-(5a+1

determiningTheFunctionDomain
-(5a+1-6

Back to the equation:

-(-(5a+1-6)



We add all the numbers together, and all the variables

-4a-(-(5a-5)=0



We calculate terms in parentheses: -(-(5a-5), so:

-(5a-5





We calculate terms in parentheses: -(-(5a-5), so:

-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





We calculate terms in parentheses: -(-(5a-5), so:

-(5a-5





We calculate terms in parentheses: -(-(5a-5), so:

-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





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-(5a-5





We calculate terms in parentheses: -(-(5a-5), so:

-(5a-5





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-(5a-5





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-(5a-5





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