If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-4b(-8b)=0
We multiply parentheses
32b^2=0
a = 32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·32·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$b=\frac{-b}{2a}=\frac{0}{64}=0$
| 17x+1x=5 | | 5(r-1)=2(r-$)-6 | | |2x-6=15 | | 7(x+2)=2x | | 4(3-x)^2=(x-5)^2 | | 13-2x=2(x-15)-1 | | X3+5x-14=0 | | 53+-22=x | | -3x-13=x | | -5+25x+-40x-2=-4x-8x | | 2y+3=3(1y+7) | | 2x+|3x-4|=11 | | 4.2-2.78=a | | 5x-3(4x-7)=4x+8 | | 6+5c=31 | | 3(x−2)+4(x+3)=6(x+1) | | 3x+2=-2* | | 2(x+3)+5=4x-5 | | F(x)=125 | | 8x+38x+3=3x+8 | | E={d,} | | 5m/2+11=25 | | 2(1–x)=12 | | X=548+.2x | | f(11)=5(11)+12 | | 1=2(3x+4)+x | | 17+6y=20 | | 1=2(3x+4 | | 2y-½=3 | | -5d=1-0 | | 7=(2x+4)/2 | | -1=3a-1 |