-4b+3(-1+b)=2(1-b)

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Solution for -4b+3(-1+b)=2(1-b) equation: 



-4b+3(-1+b)=2(1-b)

We move all terms to the left:

-4b+3(-1+b)-(2(1-b))=0

We add all the numbers together, and all the variables

-4b+3(b-1)-(2(-1b+1))=0

We multiply parentheses

-4b+3b-(2(-1b+1))-3=0



We calculate terms in parentheses: -(2(-1b+1)), so:

2(-1b+1)

We multiply parentheses

-2b+2

Back to the equation:

-(-2b+2)



We add all the numbers together, and all the variables

-1b-(-2b+2)-3=0

We get rid of parentheses

-1b+2b-2-3=0

We add all the numbers together, and all the variables

b-5=0

We move all terms containing b to the left, all other terms to the right

b=5

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