-4b-28=-7(b+4)+3b

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Solution for -4b-28=-7(b+4)+3b equation: 



-4b-28=-7(b+4)+3b

We move all terms to the left:

-4b-28-(-7(b+4)+3b)=0



We calculate terms in parentheses: -(-7(b+4)+3b), so:

-7(b+4)+3b

We add all the numbers together, and all the variables

3b-7(b+4)

We multiply parentheses

3b-7b-28

We add all the numbers together, and all the variables

-4b-28

Back to the equation:

-(-4b-28)



We get rid of parentheses

-4b+4b+28-28=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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