-4c=(5c+58)/6

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Solution for -4c=(5c+58)/6 equation: 



-4c=(5c+58)/6

We move all terms to the left:

-4c-((5c+58)/6)=0

We multiply all the terms by the denominator


-4c*6)-((5c+58)=0

Wy multiply elements

-24c^2=0

a = -24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-24)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{-48}=0$

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