-4d(d-6)=0

Solution for -4d(d-6)=0 equation:

-4d(d-6)=0

We multiply parentheses

-4d^2+24d=0

a = -4; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-4)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-4}=\frac{-48}{-8}
=+6
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-4}=\frac{0}{-8}
=0
$