-4d+(2(3+d)=-14

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Solution for -4d+(2(3+d)=-14 equation: 



-4d+(2(3+d)=-14

We move all terms to the left:

-4d+(2(3+d)-(-14)=0

We add all the numbers together, and all the variables

-4d+(2(d+3)-(-14)=0



We calculate terms in parentheses: +(2(d+3)-(-14), so:

2(d+3)-(-14

We add all the numbers together, and all the variables

2(d+3)

We multiply parentheses

2d+6

Back to the equation:

+(2d+6)



We get rid of parentheses

-4d+2d+6=0

We add all the numbers together, and all the variables

-2d+6=0

We move all terms containing d to the left, all other terms to the right

-2d=-6

d=-6/-2

d=+3

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