-4d+16=3(2d-1)-1

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Solution for -4d+16=3(2d-1)-1 equation: 



-4d+16=3(2d-1)-1

We move all terms to the left:

-4d+16-(3(2d-1)-1)=0



We calculate terms in parentheses: -(3(2d-1)-1), so:

3(2d-1)-1

We multiply parentheses

6d-3-1

We add all the numbers together, and all the variables

6d-4

Back to the equation:

-(6d-4)



We get rid of parentheses

-4d-6d+4+16=0

We add all the numbers together, and all the variables

-10d+20=0

We move all terms containing d to the left, all other terms to the right

-10d=-20

d=-20/-10

d=+2

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