-4d+2(3+d)=16

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Solution for -4d+2(3+d)=16 equation: 



-4d+2(3+d)=16

We move all terms to the left:

-4d+2(3+d)-(16)=0

We add all the numbers together, and all the variables

-4d+2(d+3)-16=0

We multiply parentheses

-4d+2d+6-16=0

We add all the numbers together, and all the variables

-2d-10=0

We move all terms containing d to the left, all other terms to the right

-2d=10

d=10/-2

d=-5

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