-4h(-5h-4)=2(10h+8)

Solution for -4h(-5h-4)=2(10h+8) equation:

-4h(-5h-4)=2(10h+8)

We move all terms to the left:

-4h(-5h-4)-(2(10h+8))=0

We multiply parentheses

20h^2+16h-(2(10h+8))=0


We calculate terms in parentheses: -(2(10h+8)), so:

2(10h+8)

We multiply parentheses

20h+16

Back to the equation:

-(20h+16)


We get rid of parentheses

20h^2+16h-20h-16=0

We add all the numbers together, and all the variables

20h^2-4h-16=0

a = 20; b = -4; c = -16;
Δ = b2-4ac
Δ = -42-4·20·(-16)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-36}{2*20}=\frac{-32}{40}
=-4/5
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+36}{2*20}=\frac{40}{40}
=1
$