-4h(h+2)=h(2h-3)

Solution for -4h(h+2)=h(2h-3) equation:

-4h(h+2)=h(2h-3)

We move all terms to the left:

-4h(h+2)-(h(2h-3))=0

We multiply parentheses

-4h^2-8h-(h(2h-3))=0


We calculate terms in parentheses: -(h(2h-3)), so:

h(2h-3)

We multiply parentheses

2h^2-3h

Back to the equation:

-(2h^2-3h)


We get rid of parentheses

-4h^2-2h^2-8h+3h=0

We add all the numbers together, and all the variables

-6h^2-5h=0

a = -6; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-6)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-6}=\frac{0}{-12}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-6}=\frac{10}{-12}
=-5/6
$