-4k-2(k-3)=1/6k+6

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Solution for -4k-2(k-3)=1/6k+6 equation: 



-4k-2(k-3)=1/6k+6

We move all terms to the left:

-4k-2(k-3)-(1/6k+6)=0



Domain of the equation: 6k+6)!=0

k∈R



We multiply parentheses

-4k-2k-(1/6k+6)+6=0

We get rid of parentheses

-4k-2k-1/6k-6+6=0

We multiply all the terms by the denominator


-4k*6k-2k*6k-6*6k+6*6k-1=0

Wy multiply elements

-24k^2-12k^2-36k+36k-1=0

We add all the numbers together, and all the variables

-36k^2-1=0

a = -36; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-36)·(-1)
Δ = -144
Delta is less than zero, so there is no solution for the equation

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