-4k-4(k-2)=3k+19

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Solution for -4k-4(k-2)=3k+19 equation: 



-4k-4(k-2)=3k+19

We move all terms to the left:

-4k-4(k-2)-(3k+19)=0

We multiply parentheses

-4k-4k-(3k+19)+8=0

We get rid of parentheses

-4k-4k-3k-19+8=0

We add all the numbers together, and all the variables

-11k-11=0

We move all terms containing k to the left, all other terms to the right

-11k=11

k=11/-11

k=-1

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