-4m(-3m+2)=12m+8

Solution for -4m(-3m+2)=12m+8 equation:

-4m(-3m+2)=12m+8

We move all terms to the left:

-4m(-3m+2)-(12m+8)=0

We multiply parentheses

12m^2-8m-(12m+8)=0

We get rid of parentheses

12m^2-8m-12m-8=0

We add all the numbers together, and all the variables

12m^2-20m-8=0

a = 12; b = -20; c = -8;
Δ = b2-4ac
Δ = -202-4·12·(-8)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-28}{2*12}=\frac{-8}{24}
=-1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+28}{2*12}=\frac{48}{24}
=2
$