-4m+28=2(2+m)

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Solution for -4m+28=2(2+m) equation: 



-4m+28=2(2+m)

We move all terms to the left:

-4m+28-(2(2+m))=0

We add all the numbers together, and all the variables

-4m-(2(m+2))+28=0



We calculate terms in parentheses: -(2(m+2)), so:

2(m+2)

We multiply parentheses

2m+4

Back to the equation:

-(2m+4)



We get rid of parentheses

-4m-2m-4+28=0

We add all the numbers together, and all the variables

-6m+24=0

We move all terms containing m to the left, all other terms to the right

-6m=-24

m=-24/-6

m=+4

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