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-4m+3/2m=-5
We move all terms to the left:
-4m+3/2m-(-5)=0
Domain of the equation: 2m!=0We add all the numbers together, and all the variables
m!=0/2
m!=0
m∈R
-4m+3/2m+5=0
We multiply all the terms by the denominator
-4m*2m+5*2m+3=0
Wy multiply elements
-8m^2+10m+3=0
a = -8; b = 10; c = +3;
Δ = b2-4ac
Δ = 102-4·(-8)·3
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14}{2*-8}=\frac{-24}{-16} =1+1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14}{2*-8}=\frac{4}{-16} =-1/4 $
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