-4m2-9m+63=0

Solution for -4m2-9m+63=0 equation:

-4m^2-9m+63=0

a = -4; b = -9; c = +63;
Δ = b2-4ac
Δ = -92-4·(-4)·63
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-33}{2*-4}=\frac{-24}{-8}
=+3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+33}{2*-4}=\frac{42}{-8}
=-5+1/4
$