-4n(3n-2)-n=-11(n-1)

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Solution for -4n(3n-2)-n=-11(n-1) equation:



-4n(3n-2)-n=-11(n-1)
We move all terms to the left:
-4n(3n-2)-n-(-11(n-1))=0
We add all the numbers together, and all the variables
-1n-4n(3n-2)-(-11(n-1))=0
We multiply parentheses
-12n^2-1n+8n-(-11(n-1))=0
We calculate terms in parentheses: -(-11(n-1)), so:
-11(n-1)
We multiply parentheses
-11n+11
Back to the equation:
-(-11n+11)
We add all the numbers together, and all the variables
-12n^2+7n-(-11n+11)=0
We get rid of parentheses
-12n^2+7n+11n-11=0
We add all the numbers together, and all the variables
-12n^2+18n-11=0
a = -12; b = 18; c = -11;
Δ = b2-4ac
Δ = 182-4·(-12)·(-11)
Δ = -204
Delta is less than zero, so there is no solution for the equation

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