-4n(n-2)=6(n+3)-11n

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Solution for -4n(n-2)=6(n+3)-11n equation: 



-4n(n-2)=6(n+3)-11n

We move all terms to the left:

-4n(n-2)-(6(n+3)-11n)=0

We multiply parentheses

-4n^2+8n-(6(n+3)-11n)=0



We calculate terms in parentheses: -(6(n+3)-11n), so:

6(n+3)-11n

We add all the numbers together, and all the variables

-11n+6(n+3)

We multiply parentheses

-11n+6n+18

We add all the numbers together, and all the variables

-5n+18

Back to the equation:

-(-5n+18)



We get rid of parentheses

-4n^2+8n+5n-18=0

We add all the numbers together, and all the variables

-4n^2+13n-18=0

a = -4; b = 13; c = -18;
Δ = b2-4ac
Δ = 132-4·(-4)·(-18)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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