-4n+n=-8(n+2)-(2-2n)

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Solution for -4n+n=-8(n+2)-(2-2n) equation: 



-4n+n=-8(n+2)-(2-2n)

We move all terms to the left:

-4n+n-(-8(n+2)-(2-2n))=0

We add all the numbers together, and all the variables

-4n+n-(-8(n+2)-(-2n+2))=0

We add all the numbers together, and all the variables

-3n-(-8(n+2)-(-2n+2))=0



We calculate terms in parentheses: -(-8(n+2)-(-2n+2)), so:

-8(n+2)-(-2n+2)

We multiply parentheses

-8n-(-2n+2)-16

We get rid of parentheses

-8n+2n-2-16

We add all the numbers together, and all the variables

-6n-18

Back to the equation:

-(-6n-18)



We get rid of parentheses

-3n+6n+18=0

We add all the numbers together, and all the variables

3n+18=0

We move all terms containing n to the left, all other terms to the right

3n=-18

n=-18/3

n=-6

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