-4n=-7n(1-2n)

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Solution for -4n=-7n(1-2n) equation:



-4n=-7n(1-2n)
We move all terms to the left:
-4n-(-7n(1-2n))=0
We add all the numbers together, and all the variables
-4n-(-7n(-2n+1))=0
We calculate terms in parentheses: -(-7n(-2n+1)), so:
-7n(-2n+1)
We multiply parentheses
14n^2-7n
Back to the equation:
-(14n^2-7n)
We get rid of parentheses
-14n^2-4n+7n=0
We add all the numbers together, and all the variables
-14n^2+3n=0
a = -14; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-14)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-14}=\frac{-6}{-28} =3/14 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-14}=\frac{0}{-28} =0 $

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