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-4p(-6p+20)-18=-5(15p-20)
We move all terms to the left:
-4p(-6p+20)-18-(-5(15p-20))=0
We multiply parentheses
24p^2-80p-(-5(15p-20))-18=0
We calculate terms in parentheses: -(-5(15p-20)), so:We get rid of parentheses
-5(15p-20)
We multiply parentheses
-75p+100
Back to the equation:
-(-75p+100)
24p^2-80p+75p-100-18=0
We add all the numbers together, and all the variables
24p^2-5p-118=0
a = 24; b = -5; c = -118;
Δ = b2-4ac
Δ = -52-4·24·(-118)
Δ = 11353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{11353}}{2*24}=\frac{5-\sqrt{11353}}{48} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{11353}}{2*24}=\frac{5+\sqrt{11353}}{48} $
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