-4p2+4p+224=0

Solution for -4p2+4p+224=0 equation:

-4p^2+4p+224=0

a = -4; b = 4; c = +224;
Δ = b2-4ac
Δ = 42-4·(-4)·224
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-60}{2*-4}=\frac{-64}{-8}
=+8
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+60}{2*-4}=\frac{56}{-8}
=-7
$