-4r+8(2r+2)=-(1r-3)

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Solution for -4r+8(2r+2)=-(1r-3) equation:



-4r+8(2r+2)=-(1r-3)
We move all terms to the left:
-4r+8(2r+2)-(-(1r-3))=0
We add all the numbers together, and all the variables
-4r+8(2r+2)-(-(r-3))=0
We multiply parentheses
-4r+16r-(-(r-3))+16=0
We calculate terms in parentheses: -(-(r-3)), so:
-(r-3)
We get rid of parentheses
-r+3
We add all the numbers together, and all the variables
-1r+3
Back to the equation:
-(-1r+3)
We add all the numbers together, and all the variables
12r-(-1r+3)+16=0
We get rid of parentheses
12r+1r-3+16=0
We add all the numbers together, and all the variables
13r+13=0
We move all terms containing r to the left, all other terms to the right
13r=-13
r=-13/13
r=-1

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