-4r+8(2r+2)=-(1r-3)

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Solution for -4r+8(2r+2)=-(1r-3) equation: 



-4r+8(2r+2)=-(1r-3)

We move all terms to the left:

-4r+8(2r+2)-(-(1r-3))=0

We add all the numbers together, and all the variables

-4r+8(2r+2)-(-(r-3))=0

We multiply parentheses

-4r+16r-(-(r-3))+16=0



We calculate terms in parentheses: -(-(r-3)), so:

-(r-3)

We get rid of parentheses

-r+3

We add all the numbers together, and all the variables

-1r+3

Back to the equation:

-(-1r+3)



We add all the numbers together, and all the variables

12r-(-1r+3)+16=0

We get rid of parentheses

12r+1r-3+16=0

We add all the numbers together, and all the variables

13r+13=0

We move all terms containing r to the left, all other terms to the right

13r=-13

r=-13/13

r=-1

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