-4t(t-2)-(t+2)=11

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Solution for -4t(t-2)-(t+2)=11 equation: 



-4t(t-2)-(t+2)=11

We move all terms to the left:

-4t(t-2)-(t+2)-(11)=0

We multiply parentheses

-4t^2+8t-(t+2)-11=0

We get rid of parentheses

-4t^2+8t-t-2-11=0

We add all the numbers together, and all the variables

-4t^2+7t-13=0

a = -4; b = 7; c = -13;
Δ = b2-4ac
Δ = 72-4·(-4)·(-13)
Δ = -159
Delta is less than zero, so there is no solution for the equation

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