-4t+3(2t+)=2(3t-3)-3

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Solution for -4t+3(2t+)=2(3t-3)-3 equation: 



-4t+3(2t+)=2(3t-3)-3

We move all terms to the left:

-4t+3(2t+)-(2(3t-3)-3)=0

We add all the numbers together, and all the variables

-4t+3(+2t)-(2(3t-3)-3)=0

We multiply parentheses

-4t+6t-(2(3t-3)-3)=0



We calculate terms in parentheses: -(2(3t-3)-3), so:

2(3t-3)-3

We multiply parentheses

6t-6-3

We add all the numbers together, and all the variables

6t-9

Back to the equation:

-(6t-9)



We add all the numbers together, and all the variables

2t-(6t-9)=0

We get rid of parentheses

2t-6t+9=0

We add all the numbers together, and all the variables

-4t+9=0

We move all terms containing t to the left, all other terms to the right

-4t=-9

t=-9/-4

t=2+1/4

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